Module 1: Measurements and Motion in 1D
"What goes up must come down."
— Isaac Newton's insight on gravity
Free fall represents one of physics' most elegant examples of how calculus-based analysis reveals the fundamental nature of gravitational motion. Beyond simple kinematic equations, you'll explore the differential equation foundations of gravity, analyze terminal velocity through drag force modeling, and apply these concepts to real-world engineering challenges like spacecraft reentry dynamics and building safety design. From Galileo's revolutionary insights to modern aerospace engineering, free fall physics connects mathematical elegance with life-saving applications in structural engineering, automotive safety, and space exploration.
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CC1.1 Solve problems of motion in one dimension
LO1.1.1 Translate from scientific notation to regular numbers
LO1.1.2 Translate from different measurement systems
★ LO1.1.3 Investigate the quantities that define motion in one dimension
★ LO1.1.4 Analyze a problem in one dimension
Click the blue buttons to go to the Open Stax reading assignments.
Watch these videos to see gravity in action and learn how to solve free fall problems. Pay attention to how we handle coordinate systems and signs!
Arrange these steps in the correct order for systematically solving free fall motion problems:
Classify each scenario based on the motion characteristics during free fall:
Click each card to test your understanding and clear up common free fall misconceptions:
NO! In a vacuum, all objects fall at the same rate (9.8 m/s²) regardless of mass. Air resistance can make heavier objects seem to fall faster in air.
YES! Even when velocity = 0 at the peak, acceleration is still -9.8 m/s² downward. This is what makes the ball start falling!
NO! Acceleration is always -9.8 m/s² downward throughout the entire flight - up, at the peak, and down.
The negative sign indicates direction. If we define upward as positive, then gravity (downward) is negative acceleration.
Advanced free fall analysis requires:
Practice Problem 1
A ball is dropped from a height of 45 m. How long does it take to hit the ground?
Given: y₀ = 45 m, y = 0 m, v₀ = 0, a = -9.8 m/s²
Find: t
Use: y = y₀ + v₀t + ½at²
0 = 45 + 0 + ½(-9.8)t²
0 = 45 - 4.9t²
4.9t² = 45
t² = 9.18
t = 3.03 seconds
Practice Problem 2
A ball is thrown upward with initial velocity 20 m/s. How high does it go?
Given: v₀ = 20 m/s, v = 0 (at maximum height), a = -9.8 m/s²
Find: maximum height (y - y₀)
Use: v² = v₀² + 2a(y - y₀)
0² = 20² + 2(-9.8)(y - y₀)
0 = 400 - 19.6(y - y₀)
19.6(y - y₀) = 400
y - y₀ = 20.4 m
Practice Problem 3
A stone is thrown downward from a 100 m cliff with initial speed 15 m/s. What is its speed when it hits the water?
Given: y₀ = 100 m, y = 0, v₀ = -15 m/s (negative because downward), a = -9.8 m/s²
Find: v
Use: v² = v₀² + 2a(y - y₀)
v² = (-15)² + 2(-9.8)(0 - 100)
v² = 225 + (-19.6)(-100)
v² = 225 + 1960 = 2185
v = -46.7 m/s
The speed (magnitude) is 46.7 m/s downward.
Advanced Problem 4: Engineering Application
Aerospace Engineering: A spacecraft heat shield test article is dropped from a high-altitude balloon at 40 km altitude. Calculate the time to reach terminal velocity and the distance traveled.
Given: Initial altitude y₀ = 40,000 m, v₀ = 0, m = 500 kg, drag coefficient analysis shows terminal velocity v_t = 200 m/s
Phase 1 - Free fall acceleration (before significant air resistance):
Time to reach 90% of terminal velocity: t = v_t/g = (0.9 × 200)/9.8 = 18.4 s
Distance during acceleration phase: y = ½gt² = ½(9.8)(18.4)² = 1,660 m
Phase 2 - Terminal velocity:
Remaining distance: 40,000 - 1,660 = 38,340 m at constant 200 m/s
Time at terminal velocity: t = 38,340/200 = 192 s
Total time: 18.4 + 192 = 210 seconds (3.5 minutes)
Advanced Problem 5: Calculus Application
Given a position function for a falling object with air resistance: y(t) = y₀ - (v_t²/g)[t + (v_t/g)(e^(-gt/v_t) - 1)], find velocity and acceleration functions.
Given: y₀ = 1000 m, v_t = 50 m/s, g = 9.8 m/s²
Solution using calculus:
Velocity: v(t) = dy/dt = -v_t(1 - e^(-gt/v_t))
Acceleration: a(t) = dv/dt = -g·e^(-gt/v_t)
Physical interpretation:
Through this university-level treatment of free fall, you have: