Module 7: Heat and Temperature
CC7.1 Solve problems involving heat and temperature
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LO7.1.1: Perform unit conversions between kelvin, degrees Celsius, and degrees Fahrenheit
LO7.1.2 Investigate the meaning of thermal equilibrium
LO7.1.3 Compute the expansion of heated or cooled objects
LO7.1.4 Compare and contrast the different states of matter
LO7.1.5 Practice using the ideal gas law to find the state of an ideal gas
LO7.1.6 Differentiate between thermal energy, temperature, and heat
LO7.1.7 Solve problems involving heat transfer, specific heat, and latent heat
★ LO7.1.8 Create machine diagrams and perform calculations from them
Read Chapter 4 of Physical Science, 13th edition by Bill Tillery McGraw Hill Education
In this module, machines are devices that operate in a cycle and that accomplish a task by taking in heat and/or work and producing an output of heat and/or work. Common examples of these machines are heat engines and refrigerators.
Time: 10:03
Topics: In this lecture we will cover machines such as heat engines and refrigerators, and the Second Law of Thermodynamics.
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Follow these steps when creating a machine diagram.
Once all of the heat and work inputs and outputs of a machine have been identified, we want some way of accessing how effective it is at doing its job. In general, the way to compute this is to take the ratio between the output that is desired and the input that must be paid for
In the case of heat engines, heat is supplied as an input and the operator pays for this heat in the cost of the fossil fuels that are needed to run the engine, and the engine has two outputs, one is desired and one is not. The desired output is the work that can be transferred to the transmission. This ratio is called the engine's efficiency, and because the output work can never be more than the input this ratio is less than one, and is normally represented as a percentage.
Where
In the case of refrigerators, electrical work is done on a gas (the refrigerant) to compress it. When the gas expands, heat is pulled from the surrounding environment thereby cooling it, but as the compressor works it gets hot and radiates heat away. The energy transfer that is desired is the heat transfer from a cold environment, and the energy transfer that the operator must pay for is the electrical work being done. This ratio is called the coefficient of performance, COP
Where
Joules are the SI unit for energy, work, and heat whereas watts are the SI units for power and rates of energy or heat transfer, and one watt equals one joule per second. The machines in this module operate in a cycle; that means that the state of the machine is exactly the same at the end of the cycle as it was at the beginning. With this being the case, the device operates the same each cycle. Because of this, it is common to talk about the input power and output power instead of input work and output work per cycle; and instead of heat per cycle we talk about the rate of heat transfer. This won't change the result when computing the metric of goodness described above.
Print off these equation sheets to help you complete the mastery assessments.
PROMT How much energy does a refrigerator remove from 100.0 g of water at 20.0℃ to make ice at -10.0℃?
Answer
Answer:
Not what you got? Watch the video to see how to solve this one.
Time: 21:31
PROMT A heat engine operates with 65.0 Kcal of heat supplied and exhausts 40.0 kcals of heat. How much work did the engine do?
Answer
Answer:
Not what you got? Watch the video to see how to solve this one.
Time: 10:08